13y^2=13

Solution for 13y^2=13 equation:

13y^2=13

We move all terms to the left:

13y^2-(13)=0

a = 13; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·13·(-13)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26}{2*13}=\frac{-26}{26}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26}{2*13}=\frac{26}{26}
=1
$